2n^2+10n-150=0

Solution for 2n^2+10n-150=0 equation:

2n^2+10n-150=0

a = 2; b = 10; c = -150;
Δ = b2-4ac
Δ = 102-4·2·(-150)
Δ = 1300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1300}=\sqrt{100*13}=\sqrt{100}*\sqrt{13}=10\sqrt{13}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{13}}{2*2}=\frac{-10-10\sqrt{13}}{4}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{13}}{2*2}=\frac{-10+10\sqrt{13}}{4}
$